Math, asked by Anonymous, 5 hours ago


 \displaystyle  \sf\red { \iiint - x \: dx dxdx}


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Answered by sajan6491
16

\displaystyle \sf\red { \iiint - x \: dx dxdx}

\displaystyle \sf\red { \int - x \: dx =   -  \frac{ {x}^{2} }{2} +C  }

\displaystyle \sf\red { \iint  \bigg(   - \frac{  {x}^{2} }{2}  + C \bigg)dxdx  }

\displaystyle \sf\red {  \int \bigg( -  \frac{ {x}^{2} }{2}   +C \bigg)dx =  \frac{ -  {x}^{3} }{6}  +Cx + C  }

\displaystyle \sf\red {  \int \bigg( -  \frac{ {x}^{3} }{6}   +Cx + C \bigg)dx   }

   \large \sf    \red{- \frac{ {x}^{4} }{12}  +  \frac{C {x}^{2} }{2}  + Cx + C}

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