Math, asked by sajan6491, 6 hours ago

\displaystyle \sf \red{\ln( \sum \limits_{a = 1}^{ \infty} \bigg( \int_{0}^{ \infty} \frac{ {x}^{a - 1} {e}^{ - \frac{x}{2018} } }{2018[(a - 1)!] ^{2} } \: dx \bigg)) }

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Answered by IamIronMan0
45

Answer:

 \huge \purple{2018 +   \ln(2019) }

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Answered by Anonymous
38

\huge\mathfrak\pink{Answer \:  refer  \: to \:  the   \: attachment}

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