Question

$divide \: the \: sum \: of \: \frac{65}{12} and \: \frac{3}{8} by \\ their\:difference$
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Answer 1

on dividing the sum of fraction by their difference we get:-

$\frac{139}{121}$

Answer 2

Answer:

$\boxed{\boxed{\bold{\dfrac{139}{121}}}}$

Step-by-step explanation:

$Given \; numbers \; = \dfrac{65}{12} \; and \; \dfrac{3}{8}\\\\\\\text{Sum of numbers = } \dfrac{65}{12} + \dfrac{3}{8}\\\\\\= \dfrac{260 + 18}{48}\\\\\\= \dfrac{278}{48}\\\\\\= \dfrac{139}{24}\\\\\\\text{Now, difference between the numbers = } \dfrac{65}{12} - \dfrac{3}{8}\\\\\\= \dfrac{130 - 9}{24}\\\\\\= \dfrac{121}{24}\\\\\\\text{Now, dividing sum by difference, we get}\\\\\\\dfrac{139}{24} \div \dfrac{121}{24}\\\\\\=\dfrac{139 \times 24}{24 \times 121}$

$\boxed{\boxed{\bold{= \dfrac{139}{121}}}}$