Question

$do \: the \: equation \: 5x + 7y = 8and10x + 14y = 4$
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Answer 1

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

Given system of equations,

5x + 7y = 8...............(1)

10x + 14y = 4.............(2)

Multiplying equation (1) by 2,we get :

$\sf{2(5x + 7y) = 16} \\ \\ \rightarrow \: \sf{10x + 14y = 16...........(3)}$

Subtracting equations (3) and (2),we get :

$\sf{(10x + 14y) - (10x + 14y) = 16 - 4} \\ \\ \large{ \leadsto \: \sf{0 = 12}}$

Since,

The result is of the form,

$\boxed{ \boxed{ \sf{n = 0}}}$

The solution set of x and y would be a null set,i.e.,

$\huge{ \sf{(x ,\: y) = (0 ,\: 0)}}$