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1. Draw a line segment BC=5.5 cm
2. Through B draw BX such that ∠CBX=60
∘
3. Draw BY⊥BX.
4. Draw ⊥ are bisector of BC so that it cuts BC at M and BY at O.
5. Draw a circle with centre O and radius OB.
6. The major are BKC of the circle contains the vertical angle 60
∘
.
7. With M as centre, draw an arc of radius 4.5 cm meeting the circle at A and A
′
.
8. △ABC or △A
′
BC is the require triangle.
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