Question

$evaluate \frac{3 {}^{3} \times 16 {}^{ - 1} }{2 {}^{ - 4} }$
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Answer 1

Step-by-step explanation:

$\frac{ {3}^{3} \times {16}^{ - 1} }{ {2}^{ - 4} } \\ = \frac{ {3}^{3} \times ({2}^{4} )^{ - 1} }{ {2}^{ - 4} } \\ = \frac{ {3}^{3} \times {2}^{ - 4} }{ {2}^{ - 4} } \\ = {3}^{3} \\ = 27$