![f(x) = \sqrt{16 - {x}^{2} } f(x) = \sqrt{16 - {x}^{2} }](https://tex.z-dn.net/?f=f%28x%29+%3D++%5Csqrt%7B16+-++%7Bx%7D%5E%7B2%7D+%7D+)
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Answer:
f(x) = √16-x²
f(x) = ( 4-x) (4+x)
using identity
(a+b) (a-b) = a²-b²
hope it will help you
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