find domain and range of function f(x)= (x-3)^1/2
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Step-by-step explanation:
Given:
F ( x ) = √ x − 3
A function starts out having a domain of all Reals ( − ∞ , ∞ )
A square root limits the function because you can't have negative numbers under the square root (they are called imaginary numbers).
This means
x − 3 ≥ 0
Simplifying:
x ≥ 3
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