Math, asked by ItzCuteAyush0276, 3 months ago


Factories  \: The \:  Given \:  Expression...
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Answered by Anonymous
27

Answer:

Question:-

\mathtt{Factorise}

\mathtt{ 125 -  {8x}^{3} - 27 {y}^{3}   - 90xy }

Formula used:-

  \mathtt{ {x}^{3}  +  {y}^{3} +  {z}^{3}   = (x + y + z)( {x}^{2} +  {y}^{2}   +  {z}^{2} - xy - yz  - zx)  }

Solution:-

\mathtt{ =  {5}^{3}  +  {( - 2x)}^{3} +  {( - 3y)}^{3}  - 3(5)( - 2x)( - 3y) }

  \mathtt{ {x}^{3}  +  {y}^{3} +  {z}^{3}   = (x + y + z)( {x}^{2} +  {y}^{2}   +  {z}^{2} - xy - yz  - zx)  }

  \mathtt{  = 5 + ( - 2xy ) + ( - 3y)( {5 +  {4}^{2}  +  {9y}^{2} + 10x - 6xy + 15y } }

\mathtt{ = (5 - 2x - 3y)(25 +  {4x}^{2}  +  {9y}^{2}  + 10x - 6xy + 15y)}

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess

please swipe the ans to right also to see remaining part because it show only half.

Answered by Hezal12
6

Answer:

 \: \mathtt{Factorise}   \\ \mathtt{ 125 - {8x}^{3} - 27 {y}^{3} - 90xy } \\ Formula \:  used:- \\ \mathtt{ {x}^{3} + {y}^{3} + {z}^{3} = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx) } \\ Solution:- \\ \mathtt{ = {5}^{3} + {( - 2x)}^{3} + {( - 3y)}^{3} - 3(5)( - 2x)( - 3y) } \\ \mathtt{ {x}^{3} + {y}^{3} + {z}^{3}   = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx) } \\ \mathtt{ =  5 + ( - 2xy ) + ( - 3y)( {5 + {4}^{2} + {9y}^{2} + 10x - 6xy + 15y } } \\ \mathtt{ = (5 - 2x - 3y)(25 + {4x}^{2} + {9y}^{2} + 10x - 6xy + 15y)}

Hope it's helpful to you :) :)

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