Math, asked by nishagoyal886, 10 months ago


factorise \:  {4y}^{2}  - 4y  + 1

Answers

Answered by BihariSwag
88

4y² - 4y + 1

4y² - 2y - 2y + 1

2y(2y - 1) -1(2y - 1)

(2y - 1) (2y - 1)

y = 1/2

Answered by ankit1459
2

Step-by-step explanation:

4y^2 -4y +1

=4y^2 -2y -2y +1

=2y(2y-1) -1(2y-1)

=(2y-1) (2y-1)

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