Question

$Factorise : 6x^{2} - {5x}^{2} - \sqrt{3x} + 12$
✔PLS GIVE CORRECT ANSWER ELSE DON'T ANSWER✔

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Answer 1

Consider the given that 6x

3

−5x

2

−13x+12

Put x=1 and we get,

6(1)

3

−5(1)

2

−13(1)+12

=6−5−13+12=0

Then, x=1 and x−1=0 is a factor.

Now figure above

6x

3

−5x

2

−13x+12=(x−1)(6x

2

+x−12)=0

⇒(x−1)(6x

2

+x−12)=0

⇒(x−1)(6x

2

+(9−8)x−12)=0

⇒(x−1)(6x

2

+9x−8x−12)=0

⇒(x−1)[3x(2x+3)−4(2x+3)]=0

⇒(x−1)(3x−4)(2x+3)=0

If x−1=0 then x=1

If 3x−4=0 then x=

3

4

If 2x+3=0 then x=

2

−3

Hence, the factor is 1,−

2

3

and

3

4

.

Answer 2

Answer:

answer :

6x² - 5x² - √3x + 12

= x² - √1.732 x + 12

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