Question

$factorise \\ {x}^{2} - 20x + 112$
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Answer 1

Answer:

it's roots are not real because d=b^2-4ac and here d is less than zero which means it has no real roots

Answer 2

$\huge\mathfrak\red{Good night}$

$factorise \\ {x}^{2} - 20x + 112$

$factorise \\ {x}^{2} - 8x - 14 x +112$

x (x-8)-14 (x-8)

x-8 =0 $$ x-14

x=8 $$ x=14