Question

$Factorise \: {x}^{2} + \frac{1}{ {x}^{2} } - 3$
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Answer 1

Answer:

• $\bold{(x-\dfrac{1}{x}-1)(x-\dfrac{1}{x}+1) }$.

Step-by-step explanation:

We have,

$\Rightarrow \bold{x^2+\dfrac{1}{x^2}-3 }$

To find,

$\Rightarrow \bold{Factors}$

Solution,

The above expression can be written as:

$\rightarrow \bold{x^2+\dfrac{1}{x^2}-2\timesx\times\dfrac{1}{x}-1 }$

We know,

• (a - b)² = a² + b² - 2ab.

Hence,

$\rightarrow \bold{(x-\dfrac{1}{x})^2-1 }$ or $\bold{(x-\dfrac{1}{x})^2-(1)^2 }$

We know,

• a² - b² = (a + b)(a -  b.

Hence,

$\rightarrow \bold{(x-\dfrac{1}{x}-1)(x-\dfrac{1}{x}+1) }$ is the factorized value.

Answer 2

Answer:

sorry I can't answer

Step-by-step explanation:

sorry