Question

$factorze: n {}^{2} - p {}^{2}$
a³+b³=(a+b)(a²-ab+b²)
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Answer 1

Answer:

$factorze: n {}^{2} - p {}^{2}$

a³+b³=(a+b)(a²-ab+b²)

Explanation:

I don't know I'm sorry so I'm asking what is the answer for this?

$factorze: n {}^{2} - p {}^{2}$

a³+b³=(a+b)(a²-ab+b²)