Question

$\fbox{FACTORIZE:-}$
$1. \: \: {a²-25}$
$2. \: \: {a {}^{8} - 36 }$
$3. \: \: { - 36 + \frac{1}{49}m^{2} }$

$4. \: \: { {x}^{4} + {y}^{4} }$
$5. \: \: {(a + b)^{2} - (b - a)^{2} }$
$6. \: \: {a^{2} - 10 + 16 }$

$7. \: \: 4 x^{2} + 8x - 5$
$8. \: \: 13 {a}^{2} + 37a - 16$
$9. \: \: 4{a}^{2} - 16a + 15$
$10. \: \: 6 {a}^{3} + 3a^{2} - 3 {a}$
$11. \: \: 3 {x}^{5} - 11x ^{3} - 4x$
$12. \: \: 6a {}^{6} - 21{a}^{4} - 12 {a}^{2}$
$\huge\fbox\red{Note:-}$
1. You have to factorise the above expressions ,not multiply.

2. Spam will be reported and spammer's account will be reported as well.
​

Answer 1

Answer:

(x-1/x)³ = x³-1/x³ - 3×x×1/x(1–1/x)

or (x-1/x)³ = x³-1/x³ - 3(1–1/x)

or (x-1/x)³ = 14 - 3(1–1/x) . . . . [Given, x³-1/x³ = 14]

Let x-1/x = a

Therefore a³ = 14 - 3a

or a³+3a-14 =0

or a³-2a²+2a²-4a+7a-14 =0

or a²(a-2) +2a(a-2) +7(a-2) =0

or (a-2)(a²+2a+7) =0

or a-2 = 0/(a²+2a+7)

or a = 2

So x-1/x = 2

Answer 2

${\huge{\bf{\pink{†{\red{\underbrace{\red{\mathbb{❤ᎯℕЅᏇℰℛ ❦:}}}}}}}}}$

Sure! Here are the factorizations for the given expressions:

1. $a^2 - 25$

Factorization: $(a - 5)(a + 5)$

2. $a^8 - 36$

Factorization: $(a^4 - 6)(a^4 + 6)$

3. $-36 + \frac{1}{49}m^2$

Factorization: $\left(\frac{1}{7}m - 6\right)\left(\frac{1}{7}m + 6\right)$

4. $x^4 + y^4$

Factorization: $(x^2 + y^2)(x^2 - y^2)$

5. $(a + b)^2 - (b - a)^2$

Simplification: $4ab$

6. $a^2 - 10 + 16$

Simplification: $(a - 2)(a - 8)$

7. $4x^2 + 8x - 5$

Factorization: $(2x - 1)(2x + 5)$

8. $13a^2 + 37a - 16$

Factorization: $(13a - 1)(a + 16)$

9. $4a^2 - 16a + 15$

Factorization: $(2a - 3)(2a - 5)$

10. $6a^3 + 3a^2 - 3a$

Factorization: $3a(a + 1)(2a - 1)$

11. $3x^5 - 11x^3 - 4x$

Factorization: $x(3x^2 + 1)(x^2 - 4)$

12. $6a^6 - 21a^4 - 12a^2$

Factorization: $3a^2(a^2 + 1)(2a^2 - 3)(a^2 - 4)$

Please note that these are the factorized forms of the given expressions.

${\huge{\bf{\blue{{\red{\underline{\red{\mathbb{❤︎thank \: you❤︎:}}}}}}}}}$

my name is Ayush Singh

class 11 biology...

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