Physics, asked by kaynat87, 1 year ago


 \fcolorbox{black}{gr}{heyy \: guys}
 \tt{do \: it}
 \mathfrak{derive \: the \: equation \: for \: inverse \: square \: rule}

Answers

Answered by Anonymous
2

\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{hello}}}}}}

Let's suppose the number of lines of force produced by an object is directly proportional to its mass, so..

n=k*m

where n is the number of lines of force produced by the mass m and k is a constant.

Now assume the density of the lines at any given point in space represents the strength of the gravitational field at that point. So at a distance r from the object the density of the lines of force is..

n/(surface area of the sphere of radius r)

which is n/(4*pir^2)=km/(4*pir^2)=Gm/(r^2)

where G=k/4*pi is a constant.

Answered by princepc076
3

Answer:

madm ji kha rhti ho ajkl kitne din ho gya ab to aajao

Similar questions