![find \: (70 {}^{2} { - 69}^{2}) + (68 {}^{2} { - 67 {}^{} }^{2}) + (66 {}^{2} { - 65}^{2}) + (2 {}^{2} { - 1 {}^{} }^{2}) find \: (70 {}^{2} { - 69}^{2}) + (68 {}^{2} { - 67 {}^{} }^{2}) + (66 {}^{2} { - 65}^{2}) + (2 {}^{2} { - 1 {}^{} }^{2})](https://tex.z-dn.net/?f=find+%5C%3A+%2870+%7B%7D%5E%7B2%7D++%7B+-+69%7D%5E%7B2%7D%29+%2B+%2868+%7B%7D%5E%7B2%7D++%7B+-+67+%7B%7D%5E%7B%7D+%7D%5E%7B2%7D%29+%2B+%2866+%7B%7D%5E%7B2%7D++%7B+-+65%7D%5E%7B2%7D%29+%2B+%282++%7B%7D%5E%7B2%7D+%7B+-+1+%7B%7D%5E%7B%7D+%7D%5E%7B2%7D%29)
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Answered by
1
Answer:
2485
Step-by-step explanation:
a^2-b^2=(a+b)(a-b)
applying this
(70+69)(1)+(68+67)(1)+.....+(2+1)(1)
1+2+3+4+....+70
sum of n natural no=n(n+1)/2
70(71)/2
35(71)
2485
hope it helps u
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