Math, asked by vedbhargava07, 2 months ago


find  \: area \: of \: rectangle \: which \: is \: 15 \ \frac{1}{3} long \: and \: 13 \ \frac{1}{2} wide \: find \: its \: area

Answers

Answered by Aditya20824
4

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Answered by Anonymous
53

\red{\maltese}\underline{\underline{\textsf{\textbf{ Given\::- }}}}

\sf Length\: of \:rectangle\: = 15 \dfrac{1}{3} units

\sf Breadth\: of \:rectangle\: = 13 \dfrac{1}{2} units

\red{\maltese}\underline{\underline{\textsf{\textbf{ To \: find\::- }}}}

Area of rectangle.

\red{\maltese}\underline{\underline{\textsf{\textbf{ Formula\::- }}}}

\large\sf\red {Area\: of\: rectangle = length \times breadth }

\red{\maltese}\underline{\underline{\textsf{\textbf{ Solution\::- }}}}

\dashrightarrow\qquad\sf Length\:of\:rectangle = 15\dfrac{1}{3} = \dfrac{46}{3} units

\dashrightarrow\qquad\sf Breadth\:of\:rectangle = 13\dfrac{1}{2} = \dfrac{27}{2} units

\dashrightarrow\qquad\sf Area \:of\:rectangle = length \times breadth

\dashrightarrow\qquad\sf =  \dfrac{46}{3} \times \dfrac{27}{2}

\dashrightarrow\qquad\sf = \dfrac{1242}{6}

\dashrightarrow\qquad\sf = \cancel\dfrac{1242}{6}

\dashrightarrow\qquad\sf = 207sq.units

\red{\maltese}\underline{\underline{\textsf{\textbf{ Therefore\::- }}}}

\large\sf\red {Area\: of\: rectangle = 207 sq.units  }

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