Question

$find \: cube \: root \: of \: the \: following \: \\ \\ \\ 1728$
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Answer 1

Answer:

Cube Root of 1728 by Prime Factorization

Prime factorization of 1728 is 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3

Simplifying the above expression: 26 × 33

Simplifying further: 123

Therefore, the cube root of 1728 by prime factorization is (2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3)1/3 = 12.

Explanation:

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Answer 2

Answer:

$\sqrt[3]{1728} = \sqrt[3]{(12 \times 12 \times 12)} = 12$

It is quite easy to find the cube root of 1728 as it is a perfect cube. Hence, the cube root of 1728 is 12.