Question

$find \: n \\ \\ 10 ^{ - 5} \times 10 ^{2n + 1} = 10 ^{13} \div 10 ^{7}$
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Answer 1

$\huge\bold\green{\star{\underline{\underline{Answer}}}}$

${10}^{-5}× {10}^{2n+1}= \frac{{10}^{13}}{10^7}}$

$\large\bold\pink{Comparing\: the\: powers}$

$-5 + 2n+1 = 13-7$

$-4+2n= 6$

$2n= 10$

$n = 5$

Hope it helps úh

Answer 2

$\Huge\mathcal\blue{\star{\underline{\underline{Answer}}}}$

$\bold{\underline{Given:}}$

$10^{-5} × 10^{2n+1} = \large\frac{10^{13}}{10^{7}}$

$\bold{\underline{To\: Find:}}$

$Value\: of\: n$

$\bold{\underline{Answer:}}$

$10^{-5} × 10^{2n+1}=\large\frac{10^{13}}{10^7}$

$\pink{Comparing\: the\: powers}$

$-5+2n+1=13-7$

$2n-4=6$

$n = 3$

Hope it helps úh