Math, asked by shalinibhola2639, 8 months ago


find \: p(0) \: p(1) \: p(2) \: for \: each \: of \: the \: following \: polynomials \:  = p(y) = y { }^{2}  - y + 1

Answers

Answered by rajeevr06
2

Step-by-step explanation:

p(y) =  {y}^{2}  - y + 1

p(0) = 1

p(1) = 1

p(2) =  {2}^{2}  - 2 + 1 = 3

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