Math, asked by radhasharma53204, 6 hours ago

$find \: the \: altitude \: of \: a \: triangle \: whose \: base \: is \: 16.4 \: cm \: and \: area \: is \: 246 \: cm ^{2}$

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Answers

Answered by deadpout06

0

Step-by-step explanation:

Area of triangle= 1/2 (base)(height)

=1/2*16.4*altitude = 246

=8.2*altitude =246

=altitude =246/8.2

=altitude =2460/82

= 30cm

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