Question

$find \: the \: factors \: of {(x - 2y)}^{3} { - 64z}^{ 3}$
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Answer 1

Answer:

Step-by-step explanation:

$(x - 2y)^3 - 64z^3$

= $\left(x-2y\right)^3-64z^3$

= $x^3-6x^2y+12xy^2-8y^3-64z^3$

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