Question

$find \: the \: inclination \: of \: the \: lines \: whose \: slopes \: are \: given \: below \: \: \: 1. \frac{1}{ \sqrt{3 \: } } \: 2. \: 1 \: 3. \sqrt{3 \: } 4 . \: - 1$
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Answer 1

ANSWER

CONCEPT USED

SLOPE OF A STRAIGHT LINE IS GIVEN BY TANGENT FUNCTION . SUPPOSE ONE COORDINATE ON X AXIS AND OTHER ON Y AXIS THEN TAN theta IS P/B . THEN WHAT IS theta. IT IS ACTUALLY A ANGLE BY WHICH A LINE INCLIED AT X AXIS

EXPLANATION

TAN theta = slope = 1/√3

1.. then theta = inclination angle = 30 degree

2..45

3.60

4. here angle is negative tangent function is negative in second and fourth quadrant

so angle is -π/4 or π-π/4 = 3π/4

here we get two values of angles . well we get two values in all cases because one value for acute angle and another for obtuse

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