Math, asked by Aneesh777, 1 year ago


find \: the \: magnitude \: of \: angle \: a \\ if \: 2(sin)^{2} a \:  - 3sin \: a \:  + 1 \:  = 0

Answers

Answered by Needthat
0

2 {sin}^{2}  \alpha  - 3 \sin \alpha  + 1 = 0 \\  \\ 2 { \sin }^{2}  \alpha  - 2 \sin\alpha  -  \sin \alpha  + 1 = 0 \\  \\2  \sin \alpha ( \sin \alpha  - 1) - 1( \sin \alpha  - 1) = 0 \\  \\ (2 \: sin \alpha  - 1)(sin \alpha  - 1) = 0 \\  \\ sin \alpha  =  \frac{1}{2}  \\  \\ sin \alpha  = 1 \\  \\  \alpha  =  {30}^{0}  \\  \\  \alpha  =  {90}^{0}

hope it helps

Answered by brunoconti
0

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST

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