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Hey !!!
(1003 )^1/3
3√1003 = (1000 + 3 ))^1/2
=> 1000^1/3 [1 + 3/1000] ^1/3
=> 3√1000 [1 + 3/1000]^1/3
=> 10[1 + 3/1000×1/3]
°•° in binomial Approximations , we know that x is very very small /1 or , x <<<<<<1
then ,( 1 + x )^n = [1+nx]
since , 10[1 +1/1000]
=> 10[1 + 0.001 ]
=> 10[1.001 ]
=> 10.01 Answer ..
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you can verify it ✔
(10.01 )³ = 1003.
1003 ≌1003.003001
hence, 1003 =1003
here approximately, RHS =LHS prooved
hence , our answer is 10.01 ✌
________________________
Hope it helps you !!!
@Rajukumar111
(1003 )^1/3
3√1003 = (1000 + 3 ))^1/2
=> 1000^1/3 [1 + 3/1000] ^1/3
=> 3√1000 [1 + 3/1000]^1/3
=> 10[1 + 3/1000×1/3]
°•° in binomial Approximations , we know that x is very very small /1 or , x <<<<<<1
then ,( 1 + x )^n = [1+nx]
since , 10[1 +1/1000]
=> 10[1 + 0.001 ]
=> 10[1.001 ]
=> 10.01 Answer ..
---------------------------------------------
you can verify it ✔
(10.01 )³ = 1003.
1003 ≌1003.003001
hence, 1003 =1003
here approximately, RHS =LHS prooved
hence , our answer is 10.01 ✌
________________________
Hope it helps you !!!
@Rajukumar111
Anonymous:
How 1/1000 = 1/100?
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