Math, asked by tintinkipgen51953, 4 days ago

$find \: the \: value \: of \: \\ {49x}^{2} + {36y}^{2} \: if \: 7x - 6y = 1 \: and \: xy = 1$

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Answered by XxSPIRITxX

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$find \: the \: value \: of \: \\ {49x}^{2} + {36y}^{2} \: if \: 7x - 6y = 1 \: and \: xy = 1$

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