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Answer:
Given:
- 2x=3y−5
- 2x−3y=−5
Now let us cube on both sides, we get,
- (2x−3y) ^3 =(−5) ^3
- (2x)^3 - (3y) ^3 - 3 × 2x × 3y (2x−3y)=−125
- 8x^3 - 27y^3 - 18xy (2x - 3y) = -125
No, substitute the value of 2x−3y=−5
Hope it helps! ❤
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