Question

$\: find \: the \: value \: of {b}^{2} - 4ac \: if \: \: {2x}^{2} + 5 \sqrt{3}x + 16 = 0$
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Answer 1

Question

Find the value of b² - 4ac if 2x² + 5√3x + 16 = 0

Solution:-

Eq:- 2x² + 5√3x + 16

Now compare with ax² + bx + c = 0

a = 2 , b = 5√3 and c = 16

We have to find discriminant (D ) = b² - 4ac

we get ,

D = ( 5√3 )² - 4 × 2 × 16

D = 75 - 128

D = - 53

When  b²– 4ac < 0

So , ax² + bx + c = 0 are unequal and not real. In this case, we say that the roots are imaginary.