Math, asked by aruhi6, 1 year ago


find \: the \: value \: of \:  k . \: x - 1 \: is \: a \: factor \: of \: p(x) \: = kx {}^{2}  -  \sqrt{2x}  \:   + 1

Answers

Answered by Perfectionist2212
1
x-1 is a factor of p(x)
So, p(1) =0
p(1)=k-√2+1
k-√2+1=0
k=√2-1
That's all....
Answered by rakeshmohata
0
f(x) = kx² - xroot2 +1
If x-1 is a factor then putting x= 1 we get the value of k
f(1) = k - root2 +1 =0
__or, k = 1-root2
Hope this is ur required answer.!
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