Question

$find \: the \: value \: of \: p(0) \: p(1) \: and \: p(2) \: for \: {y}^{2} - 2y \: + 1$
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Answer 1

Answer:

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Step-by-step explanation:

y2 -2y+1

y2 -y-y+1

y(y-1) -1 (y-1)

(y-1)(y-1)

y-1=0

y=1 ,1