Question

$find \: the \: values \: of \: k \: if 2 {x}^{2} + kx + 3 = 0 \: here \: equal \: real \: roots$

Answer 1

Hey mate here is your answer ⤵⤵⤵⤵

If the equation has equal roots then D=0

Here,a=2,b=k and c=3

Now,

$\sf b^2-4ac=0 \\ \\ \sf \implies k^2-4 (2)(3)=0 \\ \\ \sf \implies k^2-24=0 \\ \\ \sf \implies k^2=24 \\ \\ \sf \implies k=\sqrt {24} \\ \\ \sf \implies k=2\sqrt{6} or -2\sqrt {6}$

❤hope it helps you ❤