Question

$find \: the \: zero \: of \: a \: polynomial \\ \\ p(x) = {x}^{2} + 6x + 5$
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Answer 1

Answer:

(x+1)(x+5)

x+1=0

x=-1

x+5=0

x=-5

Step-by-step explanation:

x^2+6x+5

x^2+(1+5)x+5

x^2+1x+5x+5

x(x+1)+5(x+1)

(x+1)(x+5)

x+1=0

x=-1

x+5=0

x=-5

Answer 2

Answer:

Step-by-step explanation:

P(x)= x2+ 6x + 5

= x2+5x+x+5

=x(x+5)+1(x+5)

=(x+5)(x+1)

= X = -5,-1