Question

$find ther roots 2x ^{2} + 7x + 5 \sqrt{5 = 0}$
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Answer 1

Answer:

$2{x}^{2} + 7x +5\sqrt{5} = 0 \\ \\a = 2, b = 7 , c =5\sqrt{5}\\ \\ using \: formula\\ \\\huge\boxed{D = {b}^{2} - 4ac} \\ \\ D = {7}^{2} - 4× 2 × 5\sqrt{5} \\ \\ D = 49 - 40\sqrt{5}$