Question

$find x. if \frac{ \sqrt{x} }{ \sqrt{5} } = \sqrt{2} + 1$

Answer 1

Hey!!!!!!

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Refer to the attachment

=> x = 15 + 2√50
=> x = 15 + 10√2

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Hope this helps ✌️

Answer 2

$\frac{ \sqrt{x} }{ \sqrt{5} } = \sqrt{ \frac{x}{5} } \\ squaring \: both \: sides \:$
$( \sqrt{ \frac{x}{5} } ) {}^{2} = (\sqrt{2} + 1) {}^{2} \\ = > \frac{x}{5} = 2 + 1 + 2 \times \sqrt{2} \times 1 \\ \frac{x}{5} = 3 + 2 \sqrt{2} \\ x = 5(3 + 2\sqrt{2} ) \\ x = 15 + 10 \sqrt{2} \\ x = 15 + 14.14 \\ x = 29.14$
or you can just write
$x = 15 + 10 \sqrt{2}$
hope it helps mark it brainliest plz plz plz plz