Question

$for \: quar dratic \: equation \: 10x {}^{2} + 10x + 1 = 0 \\ what \: is \: the \: value \: of \: x$
please answer fast............
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Answer 1

$\huge \mathbb {\orange {\underline {\blue{\underline{ANSWER :-}}}}}$

The values of x are -0.113, -0.887.

Answer 2

Step-by-step explanation:

Given equation :

$\longrightarrow {10x}^{2} + 10x + 1 = 0$

Using the quadratic formula :

$\longrightarrow x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

$\begin{gathered}{ \textsf{ \textbf{here}}} \begin{cases} \sf{a= 10} \\ \sf{b = 10} \\ \sf{c = 1} \end{cases} \end{gathered}$

Solving for "x" :

${\sf {: \implies }} x {\sf{\frac{ - 10 \sqrt{ {(10)}^{2} - 4(10)(1) } }{2(10)}}}$

${\sf {: \implies}} x {\sf{\frac{ - 10 ±\sqrt{100 - 40} }{20}}}$

${\sf {: \implies }} x {\sf{\frac{{ - 10 ±\sqrt{60} } }{20}}}$

${\sf {: \implies }} x \sf{= \frac{ - 10 + \sqrt{60}}{20}} \: or \sf\frac{ - 10 - \sqrt{60}}{20}$${\boxed{\green{\checkmark{}}}}$