Question

$\frac{1}{16} \times ( \frac{1}{2} )^{2} = ( \frac{1}{2} )^{3(x - 2)}$
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Answer 1

Solution:-

$\rm \to \dfrac{1}{16} \times \bigg( \dfrac{1}{2} \bigg)^{2} = \bigg( \dfrac{1}{2} \bigg)^{3(x - 2)}$

$\rm \to \: \bigg(\dfrac{1}{2} \bigg) ^{4} \times \bigg( \dfrac{1}{2} \bigg) ^{2} = \bigg( \dfrac{1}{2} \bigg)^{3(x - 3)}$

Using exponential law

$\to \rm {a}^{m} \times {a}^{n} = {a}^{m + n}$

We get

$\to \rm \bigg( \dfrac{1}{2} \bigg)^{4 + 2} = \bigg( \dfrac{1}{2} \bigg)^{ 3(x - 3)}$

$\rm \to \: 4 + 2 = 3(x - 3)$

$\rm \to \: 6 = 3x - 3$

$\rm \to \: 6 + 3 = 3x$

$\rm \to3x = 9$

$\rm \to \: x = \dfrac{9}{3}$

$\rm \to \: x = 3$

Answer

=> x = 3

about Exponential law

=>The first law states that to multiply two exponential functions with the same base, we simply add the exponents. The second law states that to divide two exponential functions with the same base, we subtract the exponents. The third law states that in order to raise a power to a new power, we multiply the exponents. The fourth and fifth laws state that in order to raise a product or quotient to a power, we raise each factor to that power.

Answer 2

Answer:

Phloem is responsible for transportation of food. Phloem is composed of sieve tubes, companion cells, phloem parenchyma and bast fibres. Sieve tubes are the conducting elements in phloem.