Question

$\frac{ - 1}{2}. \frac{1}{2}. \frac{3}{2}... \: 10th$
Q - find the 10th term of ap

-1/2,1/2,3/2,...10th term ​

Answer 1

Answer:

10th term of the A.P = (17/2)

Step-by-step explanation:

We have,

A.P = (-1/2), (1/2), (3/2)...

Now,

a = (-1/2)

We know that,

Common Difference = a2 - a1

d = (1/2) - (-1/2)

d = (1/2) + (1/2)

d = (1 + 1)/2

d = 2/2

d = 1

We know that,

a(nth) = a + (n - 1)d

So,

10th term = (-1/2) + (10 - 1)(1)

a(10th) = (-1/2) + (9)(1)

a(10th) = (-1/2) + 9

a(10th) = 9 - (1/2)

Taking LCM = 2

a(10th) = (18/2) - (1/2)

a(10th) = (18 - 1)/2

a(10th) = 17/2

Hence,

10th term of the A.P = (17/2)

Hope it helped you and believing you understood it...All the best