Physics, asked by hgulia923, 8 months ago

\frac{1}{2}\log _{10}\left(2\right)+\log _{10}\left(\sqrt{x^2+4x+5}\right)-\frac{1}{2}\log _{10}\left(x^2-4x+5\right)=\frac{1}{2} Find (x)​

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Answered by nisha2425
3

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Answered by hackeranshuman28
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$\displaystyle\sum\limits_{i=0}^n i^3$; $\left(\ begin{array}{c}a\\ b\end{array}\right)$; $\left(\ frac{a^2}{b^3}\right)$; $\left.

 \frac{1}{2}\log _{10}\left(2\right)+\log _{10}\left(\sqrt{x^2+4x+5}\right)-\frac{1}{2}\log _{10}\left(x^2-4x+5\right)=\frac{1}{2} Find (x

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