Question

$\frac{1}{2a+3b} - \frac{4a-6b}{4a^{2}-9b^{2} }$

Answer 1

4a²-9b² = (2a)²-(3b)² = (2a+3b)(2a-3b) ----A

4a-6b = 2(2a-3b) -----B

B/A = 2/(2a+3b)

1/(2a+3b) - 2/(2a+3b) = -1/(2a+3b)