solve the following for x .
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HELLO DEAR,
1/(2a+b+2x) - 1 / (2x) = 1/2a + 1/b
=> (2x - 2a - b - 2x)/(2x)(2a+b+2x) = (2a + b)/2ab
= > -(2a + b)/(2x)(2a+b+2x) =(2a + b) /2ab
=> 2a + b will cancel from Both side
we get,
=> -2ab = (2x)(2a+b+2x)
=> -2ab = 4ax + 2bx + 4x²
=> 4x² + 2bx + 4ax + 2ab = 0
=> 2x(2x + b) + 2a(2x + b) = 0
=> (2x +2a)(2x + b) = 0
=> 2x + 2a = 0
x = - a
2x + b = 0
x = - b / 2
x = -a , -b/2
I HOPE ITS HELP YOU DEAR,
THANKS
1/(2a+b+2x) - 1 / (2x) = 1/2a + 1/b
=> (2x - 2a - b - 2x)/(2x)(2a+b+2x) = (2a + b)/2ab
= > -(2a + b)/(2x)(2a+b+2x) =(2a + b) /2ab
=> 2a + b will cancel from Both side
we get,
=> -2ab = (2x)(2a+b+2x)
=> -2ab = 4ax + 2bx + 4x²
=> 4x² + 2bx + 4ax + 2ab = 0
=> 2x(2x + b) + 2a(2x + b) = 0
=> (2x +2a)(2x + b) = 0
=> 2x + 2a = 0
x = - a
2x + b = 0
x = - b / 2
x = -a , -b/2
I HOPE ITS HELP YOU DEAR,
THANKS
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