Question

$(( \frac{1}{3} ) ^{ - 2} - ( \frac{1}{9} ) ^{ - 2} ) \div {3}^{ - 2}$
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Answer 1

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$\rightarrow \: (( \frac{1}{3} ) ^{ - 2} - ( \frac{1}{9} ) ^{ - 2} ) \div {3}$

$\rightarrow \: ( {( \frac{1}{3}) }^{ - 2} - ( \frac{1}{ {3}^{2} } )^{ - 2} ) \div 3$

$\rightarrow \: (( {3) }^{ 2} - { ({3}^{ - 2} )}^{ - 2} ) \div 3$

$\rightarrow \: ( {3}^{2} - {3}^{( - 2 \times - 2)} ) \div 3$

$\rightarrow \: ( {3}^{2} - {3}^{4} ) \div 3$

$\rightarrow \: \frac{(3 \times 3) - (3 \times 3 \times 3 \times 3)}{3}$

$\rightarrow \: \frac{3( (3) - (3 \times 3 \times 3 ))}{3}$

$\rightarrow 3 - 3 \times 3 \times 3$

$\rightarrow \: 3 - 27$

$\rightarrow \: - 24$