Question

$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4} and \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = - \frac{1}{8}$​

Answer 1

Answer:

Multiply first equation with 1/2 and add it with second equation we get,

1/(3x+y)=1/4

Similarly we get,

1/(3x-y)=1/2

we get,

3x=4-y,

4-2y=2

y=1,x=1

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