Question

$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4 } \\ \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = \frac{ - 1}{8}$
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Answer 1

Answer:

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Answer 2

Answer:

Hope it help

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