Question

$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4} \\ \\ \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = \frac{ - 1}{8}$
plz answer this....​

Answer 1

yo may find the attached solution

Answer 2

Step-by-step explanation:

$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4} \\ \\ \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = \frac{ - 1}{8}$

plz answer this....