Question

$( \frac{1}{4} ) {}^{ - x} \div (\frac{3}{2} ) {}^{2} = 6 {}^{ - 2}$
find the value of x please​

Answer 1

Step-by-step explanation:

${ \frac{1}{4} }^{ - x} \div { \frac{3}{2} }^{2} = {6}^{ - 2} \\ { \frac{1}{4} }^{ - x} = \frac{1}{ {6}^{2} } \times { \frac{3}{2} }^{2} \\ \frac{1}{ {4}^{ - x} } = \frac{1}{36} \times \frac{9}{4} \\ \frac{1}{ {4}^{ - x} } = \frac{1}{16} \\ \frac{1}{ {4}^{ - x} } = \frac{1}{ {4}^{2} }$

on comparing powers of both side then you will get x=-2

hope it helps