Math, asked by StudyLover13, 4 hours ago


 ({ \frac{1}{64} })^{0}  + ( {64})^{  - \frac{1}{2} }  + ( {32})^{ \frac{4}{5} }  - ( {32})^{  - \frac{4}{5} }  = ??

Answers

Answered by ItZzKhushi
1

{\huge{\underbrace{\overbrace{\color{aqua} {Question}}}}}

( \frac{1}{64})^{0}   + (64)^{  - \frac{1}{2} } + (32)^{ \frac{4}{5} } - (32)^{ -  \frac{4}{5} } = ??

\huge{\mathcal\fcolorbox{black} {cyan} {Answer}}

⇒( \frac{1}{64})^{0}   + (64)^{  - \frac{1}{2} } + (32)^{ \frac{4}{5} } - (32)^{ -  \frac{4}{5} } = ??

⇒1 +  \frac{1}{ ({64})^{ \frac{1}{2} } }  + ( {32})^{ \frac{4}{5} }  -  \frac{1}{( {32})^{ -  \frac{4}{5} } }

⇒1 +  \frac{1}{8}  +  {2}^{ \cancel5 \times  \frac{4}{ \cancel5} }  -  \frac{1}{ {2}^{ \cancel5 \times  \frac{4}{ \cancel5} } }

⇒17 +  \frac{1}{8}  -  \frac{1}{16}

⇒17 +  \frac{1}{16}

⇒17 \frac{1}{16}

Answered by BrainlyButterfly57
0

Answer:

⇒1+

(64)

2

1

1

+(32)

5

4

(32)

5

4

1

⇒1 + \frac{1}{8} + {2}^{ \cancel5 \times \frac{4}{ \cancel5} } - \frac{1}{ {2}^{ \cancel5 \times \frac{4}{ \cancel5} } } ⇒1+

8

1

+2

5

×

5

4

2

5

×

5

4

1

⇒17 + \frac{1}{8} - \frac{1}{16} ⇒17+

8

1

16

1

⇒17 + \frac{1}{16} ⇒17+

16

1

⇒17 \frac{1}{16} ⇒17

16

1

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