Question

$( \frac{1 + i}{1 - i} )^{2}$
Solve this in form of a+bi and find value of a and b​

Answer 1

Answer:

[(1+i)/(1-i)]^2

[(1+i)^2]/[(1-i)^2] (i^2=-1)

(1-1+2i)/(1-1-2i)

2i/-2i

-1 {a=-1 , b=0}

-1 + 0i

Answer 2

Answer:

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