Question

$\frac{1}{ \sqrt{2} } + \frac{1}{ \sqrt{2} } + \frac{1}{ \sqrt{2} } + \frac{1}{ \sqrt{2} }$
Please answer it correctly

Please answer it very fast

Answer 1

Answer:

$2\sqrt{2}$

Step-by-step explanation:

$\frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}} \\ \\ = 4 \times \frac{1}{\sqrt{2}} \\ \\ = \frac{4}{\sqrt{2}} \\ \\ = \frac{4 \times \sqrt{2}}{\sqrt{2} \times \sqrt{2}} \\ \\ = \frac{4\sqrt{2}}{2} \\ \\ = 2\sqrt{2}$

Answer 2

Hey

The answer is 2√2

HOPE IT HELPS.....