Question

$\frac{1}{ \sqrt{9 } - \sqrt{ 8} } \: \: \: is \: equal \: to$
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Answer 1

Answer:

√9 + √8

Step-by-step explanation:

$\frac{1}{ \sqrt{9} - \sqrt{8} } = \frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} } \\ = \frac{ \sqrt{9} + \sqrt{8} }{9 - 8} \\ = \sqrt{9} + \sqrt{8}$

The Rationalising Factor of √9 -√8 is √9+√8

We know that (a+b)(a-b) = a^2 - b^2

This will eliminate the roots making the denominator rational.

Answer 2

Answer:

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